2.2: Addition in Alphabitia (and Base-5)
Addition in Alphabitia (and Base-5)
Introduction
Recall, in Alphabitia, numbers are written in base-5 using the symbols:
0, A, B, C, D
Here’s the correspondence with base-10 numbers we’re more familiar with:
Alphabitia Symbol | Base-10 Value |
---|---|
0 | 0 |
A | 1 |
B | 2 |
C | 3 |
D | 4 |
When Alphabitians need to count beyond D, they create a new place value (just like in base-10, after 9 we start a new place with 10).
For example:
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D (4 in base-10)
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A0 (next after D, which equals 5 in base-10)
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AA (which equals 6 in base-10)
So Alphabitia works on the same principles as base-10, but instead of grouping by tens, they group by fives.
Review: Place Value in Alphabitia
In base-5, each place represents powers of 5:
Place | … | 5² | 5¹ | 5⁰ |
---|---|---|---|---|
Value | … | 25 | 5 | 1 |
Examples: What is the Alphabitia number C0A in base-10?
Let’s start by interpreting each digit in the number COA.
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C = 3 (in the 25s place → 3 × 25 = 75)
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0 = 0 (in the 5s place → 0 × 5 = 0)
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A = 1 (in the 1s place → 1 × 1 = 1)
So C0A = 76 in base-10.
Review: Blocks to Represent Numbers
We can use Alphabitia-style blocks to visualize:
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🟪 = a “flat” of 25 (5×5)
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| = a “long” of 5
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= a “unit” of 1
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Examples: How to represent the number BD using blocks?
We interpret each digit in the number BD.
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B = 2 in the 5s place → ||
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D = 4 in the 1s place → ****
So BD = 2×5 + 4×1 = 14 in base-10.
And we can represent BD using blocks as ||****
Rules for Addition in Alphabitia
Addition works the same way as in base-10:
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Add the digits in each place.
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If the sum is D or less , write it down.
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If the sum is larger than D or greater, “regroup” (just like carrying in base-10).
Important regrouping facts:
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A + D = * + **** → which means we have ***** = | which is ONE long. So A + D = A0.
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B + C = ** + *** = ***** → replaces with one long | = A0.
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D + D = **** + **** → regroup as | ***written as AC.
Examples
See the following video for the teacher working through more explanations and examples:
More Examples:
Remember the important thing here is to RE-GROUP!
Example 1: C + C
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C = 3, C = 3 → total = 6
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6 is bigger than 4, so regroup: 6 = 1 group of 5 + 1 left over
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In Alphabitia: C + C = 11
Example 2: BD + AC
Let’s add:
Step 1: Add ones place → D + C
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D = 4, C = 3 → total = 7
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7 = 1 group of 5 + 2 left over
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This is A in the long place, and B in the ones place.
Step 2: Add fives place → B + A + 1 (carry)
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B = 2, A = 1 → total = 3 longWrite D
Final Answer: DB
Check in base-10:
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BD = 14
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AC = 8
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14 + 8 = 22
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DB (base-5) = 22 ✔️
Example 3: 2-Digit Addition with Bigger Carry
Step 1: Ones → D + D = 8
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8 = 1 group of 5 + 3 left over
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Write C, carry 1
Step 2: Fives → D + D + 1 = 9
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9 = 1 group of 5 + 4 left over
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Write D, carry 1
Final Answer: 1DC
Check in base-10:
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DD = 24
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DD = 24
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Total = 48
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1DC in base-5 = 1×25 + 4×5 + 3 = 25 + 20 + 3 = 48 ✔️
Attributions
Videos Attributions: Hillary, VanSpronsen, 205 Section 3.1 Addition in Alphabitia. Upload date: October 17, 2012. Video address: https://www.youtube.com/watch?v=3krrfO3zQX4